Найдите решения уравнения на промежутке (-3П;-5П\2).
[tex]tg(2x- \frac{ \pi }{8} )= \sqrt{3} [/tex]
[tex]tg(2x- \frac{ \pi }{8} )= \sqrt{3} [/tex]
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2x-π/8=π/3+πn.n∈z2x=11π/24+πn,n∈z
x=11π/48+πn/2,n∈z
-3π<11π/48+πn/2<-5π/2
-144<11+24n<-60
-155<24n<-71
-155/24<n<-71/24
n=-6⇒x=11π/48-3π=-133π/48
n=-5⇒x=11π/48-5π/2=-109π/48
n=-4⇒x=11π/48-2π=-85π/48
n=-3⇒x=11π/48-3π/2=-61π/48