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ankakundas
@ankakundas
July 2022
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Количество различных корней уравнения на промежутке [0;[tex] \pi [/tex]]
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NNNLLL54
Verified answer
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flsh
Sin 3x + sin 7x = 2·sin 5x
2·sin 5x·cos 2x = 2·sin 5x
2·sin 5x·(cos 2x - 1) = 0
x = 0,
, π
Количество корней на промежутке [0; π] - 6.
0 votes
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Answers & Comments
Verified answer
2·sin 5x·cos 2x = 2·sin 5x
2·sin 5x·(cos 2x - 1) = 0
x = 0, , π
Количество корней на промежутке [0; π] - 6.