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ldinega
@ldinega
July 2022
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Решите уравнение [tex]( x^{2} +x)^{2}-8( x^{2} +x)+12=0[/tex]
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crdd
(х²+х)²-8(х²+х) +12=0
пусть х²+х=а
а²-8а+12=0
D=64-48=16
a=(8-4):2=2
a=(8+4):2=6
х²+х=2
х²+х-2=0
D=1+8=9
x=(-1-3):2=-2
x=(-1+3):2=1
x²+x=6
x²+x-6=0
D=1+24=25
х=(-1-5):2=-3
х=(-1+5):2=2
ответ: -2; 1; -3; 2
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Answers & Comments
пусть х²+х=а
а²-8а+12=0
D=64-48=16
a=(8-4):2=2
a=(8+4):2=6
х²+х=2
х²+х-2=0
D=1+8=9
x=(-1-3):2=-2
x=(-1+3):2=1
x²+x=6
x²+x-6=0
D=1+24=25
х=(-1-5):2=-3
х=(-1+5):2=2
ответ: -2; 1; -3; 2