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antondosaykin
@antondosaykin
July 2022
2
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Решите уравнение [tex]4 ^{x} + 3*2^{x} - 4=0[/tex]
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valeria2101
2^2x+3*2^x-4=0
2^x=y
y^2+3y-4=0
D=25=5^2
x1=1
x2=-4
2^x=1
x=0
2^x=-4
x=-2
0 votes
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YulyaYudina
2
+3*
-4=0
пусть
=t
t²+3t-4=0
D=9-4*(-4)=25
t₁=2/2=1
t₂=-8/2=-4
возвращаюсь в подстановку
=1
=2⁰
x=0
≠-4
1 votes
Thanks 0
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Answers & Comments
2^x=y
y^2+3y-4=0
D=25=5^2
x1=1
x2=-4
2^x=1
x=0
2^x=-4
x=-2
пусть =t
t²+3t-4=0
D=9-4*(-4)=25
t₁=2/2=1
t₂=-8/2=-4
возвращаюсь в подстановку
=1
=2⁰
x=0
≠-4