tex]...

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Складіть рівняння дотичної до графіка функції[tex]x^{2} -12x^{2} +8x[/tex]-3 у точці з абсцисою [tex]x_{0} =1[/tex] .

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wsaspo

Объяснение:

$f(x) = {x}^{2} - 12 {x}^{2} + 8x - 3 \\ f(x)' = 2x - 24x + 8 \\ f(x0) = 1 - 12 + 8 - 3 = - 6 \\ f(x0)' = 2 - 48 +8 = - 38 \\ y = - 6 + ( - 38) \times (x - 1) = - 6 + ( - 38x )+ 38 = 32 - 38x$

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pomozhit 23 zavdarya

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pomozhit 23 zavdarya

4 Complete the sentences with the prefixes in the (5 points) box. micro- ex- aut...

there will be a fault with your new scanner, you should return it...

5 Complete the sentences with the correct words. (5 points) 1) You should using ...

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