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Grotty
@Grotty
July 2022
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Упростите:
[tex] cos^{2} \alpha -sin^{2} \alpha -1/(sin \alpha +cos \alpha )^{2}-1[/tex]
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yarovoe
(cos²α-sin²α-1)/(sinα+cosα)²-1)=(cos²α-sin²α- (cos²α+sin²α))/
((sin²α+2sinαcosα+cos²α-1)=( cos²α-sin²α- cos²α-sin²α)/
(1+sin2α-1)=-2sin²α/2sinα·cosα=-sinα/cosα=-tgα
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Answers & Comments
((sin²α+2sinαcosα+cos²α-1)=( cos²α-sin²α- cos²α-sin²α)/
(1+sin2α-1)=-2sin²α/2sinα·cosα=-sinα/cosα=-tgα