найти предел
[tex] \lim_{x \to 0} \frac{ \sqrt{1+ x^{2} }-1 }{ \sqrt{ x^{2} +16} -4} [/tex]
[tex] \lim_{x \to 0} \frac{ \sqrt{1+ x^{2} }-1 }{ \sqrt{ x^{2} +16} -4} [/tex]
More Questions From This User See All
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Verified answer