Выполните действия.а) [tex] \frac{t}{3-t} [/tex] - [tex] \frac{3}{3-t} [/tex]б) [tex] \frac{c+d}{c-d} [/tex] * [tex] \frac{c-d}{c(c+d)} [/tex]в) [tex] \frac{a-b}{c+d} [/tex] : [tex] \frac{3(a-b)}{a(c+d)} [/tex]г) [tex] \frac{(3a)^{2} }{(4b)} [/tex]. Created by CreepyChan. algebra-ru

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$\frac{t}{3-t} - \frac{3}{3-t}= \frac{t-3}{3-t} =-1
\\\
 \frac{c+d}{c-d} \cdot\frac{c-d}{c(c+d)}= \frac{(c+d)(c-d)}{(c-d)(c+d)c} = \frac{1}{c} 
$
$\frac{a-b}{c+d} : \frac{3(a-b)}{a(c+d)}= \frac{(a-b)a(c+d)}{(c+d)3(a-b)} = \frac{a}{3} 
\\\
 \frac{(3a)^{2} }{(4b)} = \frac{9a^{2} }{4b}$

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1) t/(3-t)-3/(3-t)=(t-3)/(3-t)=-1
2/ (c+d)/(c-d)*(c-d)/c(c+d)=1/c
3) (a-b)/(c+d) : 3(a-b)/a(c+d) = (a-b)/(c+d) *a(c+d)/3(a-b)=a/3
4) (3a/4b)^2=9a^2/16b^2

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