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igorpanasevich
@igorpanasevich
August 2022
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Решите с подробным решением подстановкой [tex] \left \{ {{ x^{2}+xy- y^{2} =11} \atop {x-y=5} \right. [/tex]
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rubilovalex
X=y+5. подставляем в 1 уравнение: (y+5)^2+(y+5)*y-y^2=11; y^2+10y+25+y^2+5y-y^2=11; y^2+15y+14=0; D=15^2-4*1*14=225-56=169; y1=(-15-13)/2, y2=(-15+13)/2. y1= -14, y2= -1. x1= -14+5= -9. x2= -1+5=4. Ответ: (-9:-14), (4:-1).
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