Найдите значение выражения
(х-4у)²+4у(2х-4у) при х= - [tex] \frac{3}{5} [/tex]
(х-4у)²+4у(2х-4у) при х= - [tex] \frac{3}{5} [/tex]
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= х²-8ху+16у²+8ху-16у²=х²=(-3/5)²=9/25