1) Разложите на множители: 11x+12z(x-y)-11y
2) Внесите под знак корня -7√[tex] \frac{12}{23} [/tex]
2) Внесите под знак корня -7√[tex] \frac{12}{23} [/tex]
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1) =(11x-11y)+12z(x-y)=11(x-y)+12z(x-y)=(11+12z)(x-y)2) =-√7²*√12/23=-√49*√12/23=-√(49*12)/23=-√588/23