Решите пожалуйста[tex] {x}^{2} - 6 + 5 = 0[/tex][tex] {2x}^{2} - 5x + 4 = 0[/tex][tex] {3x}^{2} - 6x + 2 = 0[/tex]. Created by fuks81. algebra-ru

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August 2022 1 6 Report

Решите пожалуйста
[tex] {x}^{2} - 6 + 5 = 0[/tex]
[tex] {2x}^{2} - 5x + 4 = 0[/tex]
[tex] {3x}^{2} - 6x + 2 = 0[/tex]

Answers & Comments

aliyas1

${x}^{2} - 6x + 5 = 0 \\ x_{1} + x_{2} = 6 \\ x_{1} \times x_{2} = 5 \\ x_{1} = 1 \\ x_{2} = 5 \\ Ответ: (1; \: 5) \\ \\ {2x}^{2} - 5x + 4 = 0 \\ D=25 - 4 \times 2 \times 4 = - 7 \\ \\ Ответ: действ.корней \: \: нет \\ \\ {3x}^{2} - 6x + 2 = 0 \\ D = 36 - 4 \times 3 \times 2 = 12 \\ x_{1} = \frac{6 - \sqrt{12} }{2 \times 3} = \frac{6 - 2 \sqrt{3} }{6} = \\ = \frac{3 - \sqrt{3} }{3} \\ x_{2} = \frac{3 + \sqrt{3} }{3} \\ Ответ: (\frac{3 - \sqrt{3} }{3}; \: \frac{3 + \sqrt{3} }{3})$

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