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Lyavs
@Lyavs
June 2022
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найти корни:
x^{1.5} [/tex]=27
[tex]( \frac{1}{\sqrt{5} } ) ^{ \sqrt{x} } = \frac{1}{25} [/tex]
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Лотарингская
1 votes
Thanks 1
uekmyfhfp
1. x^1,5 = 27;
x^1,5 = 3^3;
x^1,5 = 3^(2*1,5);
x^1,5 = 9^1,5;
x = 9.
2. (5^(-1/2)^x^1/2 = 5^ -2;
(5^(- x/2)^1/2)= 5^-2;
(5)^(- x/4) = 5^ -2;
- x/4 = -2;
- x = - 8;
x = 8.
0 votes
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Answers & Comments
x^1,5 = 3^3;
x^1,5 = 3^(2*1,5);
x^1,5 = 9^1,5;
x = 9.
2. (5^(-1/2)^x^1/2 = 5^ -2;
(5^(- x/2)^1/2)= 5^-2;
(5)^(- x/4) = 5^ -2;
- x/4 = -2;
- x = - 8;
x = 8.