Помогите решить плиз [tex]4b {}^{2} - 16b + 12 = 0[/tex]. Created by naskabruskovskaa2437. algebra-ru

Ответ Объяснение:

tex]...

ludmilaksenija2005

Ответ $\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\la\la\la\la\ddddddddddddddddddddddddddddddddcleverdddddd\ffffffffffffffffffffffffffffffffffffffff\pppppppppppppppppppppppppppppppppppp\dddddd \displaystyle \large \boldsymbol{:}$ $\displaystyle \large \boldsymbol{ b_1=1 \ \ ; \ \ b_2=3}$

Объяснение:

$\displaystyle \Large \boldsymbol{} 4b^2-16b+12=0 \\\\4(b^2-4b+3)=0 \\\\ b^2-4b+3=0 \\\\ b^2-\underbrace{b-3b}_{-4b}+3=0 \\\\ b^2-b-(3b-3)=0 \\\\b(b-1)-3(b-1)=0 \\\\(b-1)(b-3)=0 \Longrightarrow b_1=1 \ \ ; \ \ b_2=3$

0 votes Thanks 1

kamilmatematik100504

Verified answer

Объяснение:

4в^2-16в+12=0

в^2-4в+3=0

в^2-в-3в+3=0

в(в-1)-3(в-1)=0

(в-1)(в-3)=0

в-1=0 в-3=0

в=1 в=3

Ответ : в1=1 в2=3

2 votes Thanks 1

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