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sadykov67
@sadykov67
July 2022
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[tex] \frac{ x^{3}-2 x^{2} -5x+6 }{x-2} \ \textgreater \ 0[/tex]
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amin07am
Verified answer
Отвнт ответ ответ отве т ответ ответ
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sadykov67
Спасибо
amin07am
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sedinalana
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[x²(x-1)-x(x-1)-6(x+1)]/(x-2)>0
(x-1)(x²-x-6)/(x-2)>0
x-1=0⇒x=1
x-2=0⇒x=2
x²-x-6=0
x1+x2=1 U x1*x2=-6⇒x1=-2 U x2=3
+ _ + _ +
-----------------(-2)------------(1)----------(2)-----------------(3)-------------
x∈(-∞;-2) U (1;2) U (3;∞)
0 votes
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Отвнт ответ ответ отве т ответ ответVerified answer
[x²(x-1)-x(x-1)-6(x+1)]/(x-2)>0(x-1)(x²-x-6)/(x-2)>0
x-1=0⇒x=1
x-2=0⇒x=2
x²-x-6=0
x1+x2=1 U x1*x2=-6⇒x1=-2 U x2=3
+ _ + _ +
-----------------(-2)------------(1)----------(2)-----------------(3)-------------
x∈(-∞;-2) U (1;2) U (3;∞)