Решите систему уравнений
[tex]\left \{ {{2x^{2}y-y=7} \atop {xy-x+3y-3=0}} \right.[/tex]
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2x²y-y=7, xy-x+3y-3=01) x(y-1)+3(y-1)=0
(x+3)(y-1)=0
x=-3 or y=1
2) x=-3
2*(-3)²y-y=7
18y-y=7
17y=7/:17
y=7/17
3) y=1
2x²*1-1=7
2x²=8/:2
x²=4
x=±2
Ответ: (2;1), (-2;1), (-3, 7/17)