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плавчиха
@плавчиха
July 2022
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1.[tex]( \frac{16}{c}) ^{ \frac{1}{3} }*(0,5c ^{-2}) ^{ \frac{2}{15} } / \sqrt[5]{2c ^{7} } [/tex]
2. [tex](3d ^{ \frac{3}{4} } / \sqrt[3]{d ^{ \frac{1}{4} } *81 * d ^{ \frac{-3}{2} } })^{-6} [/tex]
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sangers1959
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1. (16/c)¹/³*(0,5c⁻²)²/¹⁵/(2c⁷)¹/⁵=2⁴/³*c⁻¹/³*2⁻²/¹⁵*c⁻⁴/¹⁵*2⁻¹/⁵*c⁻⁷/⁵=
=(2⁴/³*2⁻²/¹⁵*2⁻¹/⁵)*(c⁻¹/³*c⁻⁴/¹⁵*c⁻⁷/⁵=2¹*c⁻²=2/c².
2. ((3*d³/⁴))/∛(d¹/⁴*81*d⁻³/²))⁻⁶=(3*d³/⁴)⁻⁶/(∛(3⁴*d⁻⁵/⁴)⁻⁶=
=(3⁻⁶*d⁻⁹/²)/(3⁴*d⁻⁵/⁴)⁻²=(3⁻⁶*d⁻⁹/²)/(3⁻⁸*d⁵/²)=3²*d⁻⁷=3²/d⁷=9/d⁷.
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Answers & Comments
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1. (16/c)¹/³*(0,5c⁻²)²/¹⁵/(2c⁷)¹/⁵=2⁴/³*c⁻¹/³*2⁻²/¹⁵*c⁻⁴/¹⁵*2⁻¹/⁵*c⁻⁷/⁵==(2⁴/³*2⁻²/¹⁵*2⁻¹/⁵)*(c⁻¹/³*c⁻⁴/¹⁵*c⁻⁷/⁵=2¹*c⁻²=2/c².
2. ((3*d³/⁴))/∛(d¹/⁴*81*d⁻³/²))⁻⁶=(3*d³/⁴)⁻⁶/(∛(3⁴*d⁻⁵/⁴)⁻⁶=
=(3⁻⁶*d⁻⁹/²)/(3⁴*d⁻⁵/⁴)⁻²=(3⁻⁶*d⁻⁹/²)/(3⁻⁸*d⁵/²)=3²*d⁻⁷=3²/d⁷=9/d⁷.