Найдите производную функции
1) [tex]y=lnx+e^{3x} [/tex]
2)[tex]y=3log _{2}x-e ^{2} [/tex]
1) [tex]y=lnx+e^{3x} [/tex]
2)[tex]y=3log _{2}x-e ^{2} [/tex]
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Answers & Comments
2) y = 3 lnx / ln 2 - e^2
y' = 3 / (x ln 2)