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ksyunechka98
@ksyunechka98
July 2022
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помогите решить: [tex] (x+1)^{2} >4x[/tex]
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ewgenijbark
Verified answer
Х²+2х+1>4x
x²+2x-4x+1>0
x²-2x+1>0
(x-1)²>0
x-любое число, т.к. при любом х выражение (х-1)² будет положительно
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ksyunechka98
(x-1)^2<=0
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tex]=0...
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Answers & Comments
Verified answer
Х²+2х+1>4xx²+2x-4x+1>0
x²-2x+1>0
(x-1)²>0
x-любое число, т.к. при любом х выражение (х-1)² будет положительно