Решите пожалуйста!!!!
[tex] {x}^{6} - {x}^{4} - {x}^{2} + 1[/tex]
[tex]8 {x}^{3} - \frac{1}{27} [/tex]
[tex] {x}^{6} - {x}^{4} - {x}^{2} + 1[/tex]
[tex]8 {x}^{3} - \frac{1}{27} [/tex]
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Verified answer
X⁶-x⁴-x²+1=x⁴*(x²-1)-(x²-1)=(x²-1)*(x⁴-1)=(x-1)*(x+1)*(x²-1)*(x²+1)==(x-1)*(x+1)*(x-1)*(x+1)*(x²+1)=(x-1)²*(x+1)²*(x²+1).
8x³-1/27=(2x)³-(1/3)³=(2x-1/3)*(4x²+(2/3)*x+1/9).