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Nikitos1234566
@Nikitos1234566
August 2022
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Объяснить несложное тригонометрическое тождество [tex]cos^{2} (\frac{ \pi }{4} +2 \alpha ) = sin^{2} ( \frac{ \pi }{4} -2\alpha) [/tex]
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sedinalana
Verified answer
Cos²(π/4+2a)=(1+cos(π/2+4a))/2=1/2-1/2*sin4a
sin²(π/4-2a)=(1-cos(π/2-4a))/2=1/2-1/2*sin4a
1/2-1/2*sin4a=1/2-1/2*sin4a
---------------------------------------
cos(π/2+a=-sina
cos(π/2-a)=sina
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Verified answer
Cos²(π/4+2a)=(1+cos(π/2+4a))/2=1/2-1/2*sin4asin²(π/4-2a)=(1-cos(π/2-4a))/2=1/2-1/2*sin4a
1/2-1/2*sin4a=1/2-1/2*sin4a
---------------------------------------
cos(π/2+a=-sina
cos(π/2-a)=sina