Помогите решить.
[tex]sinx*sin3x+sin4x*sin8x=0[/tex]
[tex]1+ctgx - cos^2x=sin^2x [/tex]
[tex]sin7x+cos^2 2x=sin^2 2x+sinx[/tex]
1+ctgx-cos^2x=sin^x;
1+ctgx-cos^2x=1-cos^2x:
ctgx=0 x=pi/2+2pik (k E Z)
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Answers & Comments
1+ctgx-cos^2x=sin^x;
1+ctgx-cos^2x=1-cos^2x:
ctgx=0 x=pi/2+2pik (k E Z)