tex]...

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[tex] \sqrt{50} cos^{2} \frac{3 \pi }{8} - \sqrt{50} sin^{2} \frac{3 \pi }{8} [/tex]

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$\sqrt{50}cos^2\frac{3\pi}{8}-\sqrt{50}sin^2\frac{3\pi}{8}=\sqrt{50}cos\frac{3\pi }{4}=\\\\=\sqrt{50}\cdot \frac{-\sqrt2}{2}=-\frac{\sqrt{100}}{2}=-5$

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