найти нули функции
[tex]y = 2x {}^{2} - 3x[/tex]
[tex]y = 2x {}^{2} - 18[/tex]
[tex]y = 2x {}^{2} - 3x[/tex]
[tex]y = 2x {}^{2} - 18[/tex]
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Ответ:
1)2х^2-3х=0
х(2х-3)=0
х=0 или 2х-3=0
2х=3
х=3/2
2)2х^2-18=0
2х^2=18
х^2=9
х=+-3