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ДженниЛенни
@ДженниЛенни
November 2021
1
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Решите, пожалуйста, неравенство
[tex]5^{\frac{x^2-3x-2}{6-x} } \geq 0,2[/tex]
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Answers & Comments
MizoriesKun
x²-3x-2
5^( ------------) ≥ 0,2 0,2=1/5 =5⁻¹
6-x
x²-3x-2
5^( ------------) ≥ 0,5⁻¹
6-x
x²-3x-2
------------- ≥ -1
6-x
x²-3x-2 ≥ -1*(6-x)
x²-3x-2 ≥ x-6
x²- 4x+4 ≥ 0
D=16-16=0
x=4/2=2
______+____2______+_____
x(-∞;2)∪(2;+∞)
2 votes
Thanks 1
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Answers & Comments
5^( ------------) ≥ 0,2 0,2=1/5 =5⁻¹
6-x
x²-3x-2
5^( ------------) ≥ 0,5⁻¹
6-x
x²-3x-2
------------- ≥ -1
6-x
x²-3x-2 ≥ -1*(6-x)
x²-3x-2 ≥ x-6
x²- 4x+4 ≥ 0
D=16-16=0
x=4/2=2
______+____2______+_____
x(-∞;2)∪(2;+∞)