найдите значение выражения [tex]sin 3\pi /2 - sin (-\pi/2)+tg^2 *2\pi/3 [/tex]
sin(3pi/2)=-1; -sin(-pi/2)=-sin(3pi/2)=--1=+1; tg(2pi/3)=-sqrt(3) (-sqrt(3))^2=3
-1+1+3 = 3
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sin(3pi/2)=-1; -sin(-pi/2)=-sin(3pi/2)=--1=+1; tg(2pi/3)=-sqrt(3) (-sqrt(3))^2=3
-1+1+3 = 3