Даю 25 БАЛЛОВ. Помогите решить неравенство [tex] \sqrt{5-x^{2} } \ \textgreater \ x-1[/tex]. Created by Samat22. algebra-ru

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August 2022 1 6 Report

Даю 25 БАЛЛОВ. Помогите решить неравенство
[tex] \sqrt{5-x^{2} } \ \textgreater \ x-1[/tex]

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wnull $\sqrt{5-x^2} \ \textgreater \ x -1 \\
( \sqrt{5-x^2})^2 \ \textgreater \ (x -1)^2 \\
5-x^2\ \textgreater \ x^2-2x+1 \\
5-x^2-x^2+2x-1\ \textgreater \ 0 \\ 
4-2x^2+2x\ \textgreater \ 0 \\
-2x^2+2x+4\ \textgreater \ 0 \\
x^2-x-2 \ \textgreater \ 0 \\ 
x_1=2; \\ 
x_2=-1;$

2 votes Thanks 0

Samat22 Вы неправильно решили, ответ должен получиться [-sqrt(5);2)

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