1. Решите систему неравенств [tex] \left \{ {{2-3x <2x+12} \atop {4x+52 \geq 0}} \right. [/tex]

2. Внесите множитель под знак корня [tex] \frac{1}{2} \sqrt{8a.} [/tex]

3. Найдите значение выражения [tex] \sqrt{ x^{2} -2x+1} [/tex]
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