Реши уравнение: [tex]\frac{1}{6r-1} + \frac{1}{3r-2}=0[/tex] Ответ: r=[tex]\frac{...}{...}[/tex]. Created by ksenyadanilova04. algebra-ru

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ksenyadanilova04 @ksenyadanilova04

July 2022 1 12 Report

Реши уравнение:
[tex]\frac{1}{6r-1} + \frac{1}{3r-2}=0[/tex]

Ответ: r=[tex]\frac{...}{...}[/tex]

Answers & Comments

d0r0tt

Ответ:

$x\neq \frac{1}{6}, x\neq \frac{2}{3}\\\frac{3x-2+6x-1}{(6x-1)*(3x-2)}=0\\\frac{9x-3}{(6x-1)*(3x-2)}=0\\9x-3=0\\9x=3\\x=\frac{1}{3}, x\neq \frac{1}{6}, x\neq \frac{2}{3}\\otvet: x=\frac{1}{3}$

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