Найдите область определения функции:
[tex]y = \sqrt{2x +8} [/tex]
[tex]y = \sqrt{(3x-18)^{-1}} [/tex]
[tex]y = \sqrt{10 + 3x - x2} [/tex]
[tex]y = \sqrt{2x +8} [/tex]
[tex]y = \sqrt{(3x-18)^{-1}} [/tex]
[tex]y = \sqrt{10 + 3x - x2} [/tex]
More Questions From This User See All
Answers & Comments