Найдите производную функции [tex]y=20x^{5}+10x^{2}+5x+2[/tex]. Created by dedaliikar. matematika-ru

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heohiro4

Ответ:

Пошаговое объяснение:

y'= 20*5x⁵⁻¹+10*2*x²⁻¹+5*1+0= 100x⁴+20x+5

2 votes Thanks 0

Evgenia4836

Verified answer

Ответ:

$y'=20x^5+10x^2+5x+2\\y'=\frac{d}{dx}(20x^5+10x^2+5x+2)\\ y'=\frac{d}{dx} (20x^5)+\frac{d}{dx} (10x^2)+\frac{d}{dx}(5x)+\frac{d}{dx}(2)\\ y'=20*5x^4+10*2x+5=0\\y'=100x^4+20x+5$

Пошаговое объяснение:

y'=100x^4+20x+5

1 votes Thanks 1

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