Решить неравенство y'>0, если
[tex]y = \frac{3}{5} x ^{ \frac{5}{ 3} } + \frac{3}{2} x ^{ \frac{4}{3} } [/tex]
[tex]y = \frac{3}{5} x ^{ \frac{5}{ 3} } + \frac{3}{2} x ^{ \frac{4}{3} } [/tex]
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+ - +
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- 2 0
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Ответ : x ∈ (- ∞ ; - 8) ∪ (0 ; + ∞)