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[tex]1) \frac{y}{y+3} - \frac{1}{y-3} = \frac{18}{y^{2}-9 } )
2) \frac{7}{y+2} - \frac{8}{y ^{2}-4}= \frac{y}{y-2} [/tex]
[tex]1) \frac{y}{y+3} - \frac{1}{y-3} = \frac{18}{y^{2}-9 } )
2) \frac{7}{y+2} - \frac{8}{y ^{2}-4}= \frac{y}{y-2} [/tex]
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