Вычислите: а) (2целых 2/7)^17 (7/16)^17 б) [tex] \frac{5^6125}{25^4} [/tex]. Created by Murashov001. algebra-ru

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June 2022 1 5 Report

Вычислите:
а) (2целых 2/7)^17 (7/16)^17
б) [tex] \frac{5^6125}{25^4} [/tex]

Answers & Comments

DrunkHedgehog 1. $(2 \frac{2}{7})^{17} (\frac{7}{16})^{17} =(\frac{16}{7})^{17} (\frac{16}{7})^{-17} ==(\frac{16}{7})^{17-17}=(\frac{16}{7})^{0}=1$
2, $\frac{5^65^3}{(5^2)^4}= \frac{5^{6+3}}{5^{2*4}} = \frac{5^9}{5^8} =5^{9-8}=5^1=5$

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