решите методом интервалов неравенства[tex]\frac{ x^{2} -4x-12}{x-2}\ \textless \ 0[/tex]. Created by NellRus1. algebra-ru

__________________________________x²-4x-12=0D=b²-4ac=16-4*1*(-12)=16+48=64x1=x2=x²-4x-12=(x-6)(x+2)___________________________________Нули функции: x=6, x=-2, x=2Ответ: (-∞;-2)U(2;6)График смотри во вложении.

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NellRus1 @NellRus1

September 2021 1 8 Report

решите методом интервалов неравенства
[tex]\frac{ x^{2} -4x-12}{x-2}\ \textless \ 0[/tex]

Answers & Comments

MashaBaggins $\frac{x^2-4x-12}{x-2}\ \textless \ 0$
__________________________________
x²-4x-12=0
D=b²-4ac=16-4*1*(-12)=16+48=64
x1= $\frac{-b+ \sqrt{D} }{2a}= \frac{4+8}{2}=6$
x2= $\frac{-b- \sqrt{D} }{2a}= \frac{4-8}{2}=- \frac{4}{2}=-2$
x²-4x-12=(x-6)(x+2)
___________________________________

$\frac{(x-6)(x+2)}{x-2}\ \textless \ 0$
Нули функции: x=6, x=-2, x=2
Ответ: (-∞;-2)U(2;6)
График смотри во вложении.

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