[tex](3 \sqrt{11}-4)(3 \sqrt{11} +4)[/tex]. Created by stas020199. algebra-ru

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stas020199 @stas020199

July 2022 1 10 Report

[tex](3 \sqrt{11}-4)(3 \sqrt{11} +4)[/tex]

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90misha90

Verified answer

$(a)^2-(b)^2=[(a)-(b)]*[(a)+(b)]$

$a=3 \sqrt{11}$ and $b=4$

$(3 \sqrt{11}-4)(3\sqrt{11}+4)=[(3 \sqrt{11} )-(4)]*[( 3\sqrt{11} )+(4)]=$

$=(3 \sqrt{11} )^2-(4)^2=3^2*( \sqrt{11} )^2-4^2=9*11-16=99-16=83$

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