Решите системы уравнений.
[tex] \left \{ {{x+y=2} \atop { x^{2}- 2y=12} \right. [/tex]
[tex] \left \{ {{x+y=5} \atop {xy=-14}} \right. [/tex]
[tex] \left \{ {{x+y=2} \atop { x^{2}- 2y=12} \right. [/tex]
[tex] \left \{ {{x+y=5} \atop {xy=-14}} \right. [/tex]
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Verified answer
X+y=2x²-2y=12
y=2-x
x²-2(2-x)=12
x²+2x-16=0
D=68
x₁=(-2-2√17)/2=-1-√17 y1=3+√17
x₂=-1+√17 y2=3-√17
x+y=5
xy=-14
y=5-x
x(5-x)=-14
-x²+5x=-14
x²-5x-14=0
D=25+4*14=25+56=81=9²
x1=(5-9)/2=-2 y1=7
x2=(5+9)/2=7 y2=-2