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pognalitude
@pognalitude
August 2022
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решите графически неравенство
x-3<= корень3+x
[tex]x - 3 \leqslant \sqrt{3 + x} [/tex]
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wejde
x-3≤√(3+x)
x∈[-3;6]
График во вложении.
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Answers & Comments
x-3≤√(3+x)
x∈[-3;6]
График во вложении.