сократить дробь [tex]\frac{(x-3)^2 -2}{x^2-1}[/tex]. Created by Murad313. algebra-ru

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[tex]\frac{(x-3)^2 -2}{x^2-1}[/tex]

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SYSTEMCORE

$\displaystyle \frac{(x-3)^2-2}{x^2-1}=\frac{x^2-6x+9-2}{x^2-1}=\frac{x^2-6x+7}{x^2-1}=\frac{x^2-1-6x+8}{x^2-1}=\\\\\\=\boxed{1-\frac{6x-8}{x^2-1}}$

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arifmeticheskaya progressiya a7 a19126 najti a13

tex pomogite reshit primer i pozhalujsta podskazhite pochemu tam poluchaetsya e 2

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razlozhit na mnozhiteli xy 1 yx 1

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