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August 2022 1 4 Report

Решить уравнений по алгебре помогите пож спасибо [tex]10a^{2} -6a+5 \alpha \beta -3 \beta \\ ---------- \\ 5a^{2}-8a+3[/tex]

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Lemon4iki $10a^{2} -6a+5a \beta -3 \beta=(10a^2+5a\beta)-(6a+3\beta)=\\=5a(2a+\beta)-3(2a+\beta)=(2a+\beta)(5a-3)
\\\\ 5a^{2}-8a+3=5(a-a_1)(a-a_2)=5(a-1)(a-0.6)
\\D=64-60=4\\a_1=\frac{8+2}{10}=1\\a_2=\frac{8-2}{10}=0.6$

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