Решите уравнение:
[tex]1) \frac{y-1}{2}= \frac{3y}{5}+2[/tex]
[tex]2) 5y^{2}-2y=0 [/tex]
[tex]1) \frac{y-1}{2}= \frac{3y}{5}+2[/tex]
[tex]2) 5y^{2}-2y=0 [/tex]
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