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edgelive
@edgelive
July 2022
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Найдите производную функции f(x)= cosx-(1/3)cos³x и вычислите производную от [tex] \pi /6
[/tex]
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sedinalana
Verified answer
F`)x)=-sinx-cos²x*(-sinx)=-sinx+cos²xsinx=sinx(cos²x-1)=sinx*(-sin²x)=-sin³x
f`(π/6)=-sin³π/6=-1/8
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Answers & Comments
Verified answer
F`)x)=-sinx-cos²x*(-sinx)=-sinx+cos²xsinx=sinx(cos²x-1)=sinx*(-sin²x)=-sin³xf`(π/6)=-sin³π/6=-1/8