[tex] 3(x+1)(x+2)=9+(3x-4)(x+2)[/tex]. Created by 12500. algebra-ru

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July 2022 1 19 Report

[tex] 3(x+1)(x+2)=9+(3x-4)(x+2)[/tex]

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Мilkа $3(x+1)(x+2)=9+(3x-4)(x+2) \\ 3(x^2+2x+x+2)=9+(3x^2+6x-4x-8) \\ 3x^2+9x+6=9+3x^2+2x-8 \\ 3x^2+9x+6-9-3x^2-2x+8=0 \\ 7x+5=0 \\ 7x=-5 \\ x= \frac{-5}{7} =- \frac{5}{7}$

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