Решите пжл уравнение срочно!!
[tex]sin^2(\frac{\pi}{2}-x)-cos(\frac{\pi}{2}-x)cosx=0[/tex]
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Решите пжл уравнение срочно!!
[tex]sin^2(\frac{\pi}{2}-x)-cos(\frac{\pi}{2}-x)cosx=0[/tex]
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Answers & Comments
cos^2(x)-sinxcosx=0
cosx(cosx-sinx)=0
cosx=0 sinx=cosx
x= п/2+пk tgx=1
x=п/4+пk