tex]...

HavaBekova2005ing @HavaBekova2005ing

July 2022 2 7 Report

Вынесите множитель из-под знака корня:
а)
[tex] \sqrt{ \frac{72}{121} } [/tex]
б)
[tex] \sqrt{ \frac{48}{225} } [/tex]
в)
[tex] \sqrt{ \frac{81}{125} } [/tex]
г)
[tex] \sqrt{ \frac{49}{216} } [/tex]

andreipeniginm5

$\displaystyle \tt a). \ \ \sqrt{\frac{72}{121}}=\frac{\sqrt{36\cdot2}}{\sqrt{121}}=\frac{6\sqrt{2}}{11};$

$\displaystyle \tt b). \ \ \sqrt{\frac{48}{225}}=\frac{\sqrt{16\cdot3}}{\sqrt{225}}=\frac{4\sqrt{3}}{15};\\\\\\c). \ \ \sqrt{\frac{81}{125}}=\frac{\sqrt{81}}{\sqrt{25\cdot5}}=\frac{9}{5\sqrt{5}}=\frac{9\sqrt{5}}{25};\\\\\\d). \ \ \sqrt{\frac{49}{216}}=\frac{\sqrt{49}}{\sqrt{36\cdot6}}=\frac{7}{6\sqrt{6}}=\frac{7\sqrt{6}}{36};$

7 votes Thanks 21

HavaBekova2005ing спасибо

Regent1828

Verified answer

Смотри ответы в прикрепленном фаиле

35 votes Thanks 74

Regent1828 Да не за что..)))

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