Verified answer

√f(x) > √g(x) ⇔ g(x) ≥ 0    f(x) > g(x)

√x > √(2x - 3)

2x - 3 ≥ 0   x ≥ 1.5

x > 2x - 3

x < 3

ответ x ∈ [1.5, 3)