[tex] \frac{3}{ \sqrt{3}+\sqrt{2} }+\frac{5}{ \sqrt{3}- \sqrt{2} } [/tex]. Created by gaz548. algebra-ru

tex]...

lara164

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=3(√3-√2) + 5(√3+√2) - это над дробной чертой, а под чертой общий знаменатель(√3-√2)(√3+√2)=(3√3-3√2+5√3+5√2) И ВСЕ ЭТО ДЕЛИТЬ НА (3-2)=
=8√3-3√2

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inblu

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$\frac{3}{ \sqrt{3}+ \sqrt{2}}+ \frac{5}{\sqrt{3}-\sqrt{2}}= \frac{3(\sqrt{3}-\sqrt{2})+5(\sqrt{3}+ \sqrt{2})}{(\sqrt{3}+ \sqrt{2})(\sqrt{3}- \sqrt{2})}= \frac{3 \sqrt{3}-3 \sqrt{2}+5\sqrt{3}+ 5\sqrt{2}}{(\sqrt{3})^2- (\sqrt{2})^2}= \\ = \frac{8\sqrt{3}-2 \sqrt{2}}{3-2}=8\sqrt{3}-2 \sqrt{2}$

2 votes Thanks 1

gaz548 Сяпки ))00):33333

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