Вычислить предел:
[tex]\lim_{n \to \infty} \frac{(n+1)!+(n+2)!}{(n+3)!}[/tex]
[tex]\lim_{n \to \infty} \frac{(n+1)!+(n+2)!}{(n+3)!}[/tex]
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Answers & Comments
Сокращаем на (n+1)!
(1+n+2)/((n+2)*(n+3))=1/(n+2)
Предел равен 0.