Найдите корень уравнения:
1) [tex] \frac{3m+5}{4} = \frac{5m+1}{3}2)\frac{5x+3}{5} = \frac{x-5}{8} [/tex]
1) [tex] \frac{3m+5}{4} = \frac{5m+1}{3}2)\frac{5x+3}{5} = \frac{x-5}{8} [/tex]
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1ОЗ 12
3(3m+5)=4(5m+1)
9m+15=20m+4
20m-9m=15-4
11m=11
m=1
2
ОЗ 40
8(5x+3)=5(x-5)
40x+24=5x-25
40x-5x=-25-24
35x=-49
x=-49/35
x=-1,4