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[tex] \sqrt{64 } - 10 \sqrt{0.16} [/tex]
[tex] \sqrt{ {26 }^{2} - {10}^{2} } [/tex]
[tex] \sqrt{64 } - 10 \sqrt{0.16} [/tex]
[tex] \sqrt{ {26 }^{2} - {10}^{2} } [/tex]
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Answers & Comments
2) √(26-10)·(26+10) = √16·36 = √16·√36 = 4·6 = 24